12c^2+13c-35=0

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Solution for 12c^2+13c-35=0 equation:


Simplifying
12c2 + 13c + -35 = 0

Reorder the terms:
-35 + 13c + 12c2 = 0

Solving
-35 + 13c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-7 + -3c)(5 + -4c) = 0

Subproblem 1

Set the factor '(-7 + -3c)' equal to zero and attempt to solve: Simplifying -7 + -3c = 0 Solving -7 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -3c = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -3c = 0 + 7 -3c = 0 + 7 Combine like terms: 0 + 7 = 7 -3c = 7 Divide each side by '-3'. c = -2.333333333 Simplifying c = -2.333333333

Subproblem 2

Set the factor '(5 + -4c)' equal to zero and attempt to solve: Simplifying 5 + -4c = 0 Solving 5 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -4c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -4c = 0 + -5 -4c = 0 + -5 Combine like terms: 0 + -5 = -5 -4c = -5 Divide each side by '-4'. c = 1.25 Simplifying c = 1.25

Solution

c = {-2.333333333, 1.25}

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